How are QCM results influenced by the lateral distribution of the measured layer?
Michael Rodal, PhD Dec 3, ’19 ~ 5 min

How are QCM results influenced by the lateral distribution of the measured layer?

In the context of QCM-data quantification, it is repeatedly stated that the layer at the surface should be evenly distributed over the sensor surface. Why is this so often stressed, and what will the consequence be if it is not fulfilled? Here we explain the reasoning behind the uniformity requirement and explain possible consequences if it is not fulfilled.

Oscillation amplitude distribution

The QCM surface is oscillating back and forth and it is the coupling of mass to this oscillation that is the basic sensing principle. However, the amplitude of oscillation is not constant across the crystal surface. How it varies depends on the geometry of the sensor and its electrodes. Standard, disk-like sensors have, to a good approximation, a radial dependence, A(r), according to Eq. 1.

Radial amplitude distribution The maximum oscillation amplitude, A0, is reached in the middle of the crystal at r=0, and then the amplitude decreases towards the edge, to reach close to zero displacement at the edge, or even before the edge. The width of the gaussian, c, is different for different harmonics. The higher the overtone, the sharper the gaussian, see Fig 1.

QCM Gaussian

Figure 1. Normalized distribution of the crystal oscillation amplitude at n = 1, 3, 5 and 7 for a 5 MHz crystal, measured at Biolin Scientific. The width of the gaussian depends on the overtone number, the higher the harmonic the sharper the Gaussian. The dashed lines indicate the top (large dashed circle) and bottom electrodes (small dashed circle). The brown ellipses represent cross-sections of the top O-ring.

Mass deposited at different radial positions will generate different QCM responses

The force exerted on a particle that is fixed on the sensor surface is directly proportional to the amplitude of oscillation at the fixing point times the mass of the particle. And Newton taught us that the force on the sensor is equal in size to that of the force on the particle. It is then easy to understand that a particle placed at the crystal center will cause a larger force, and hence frequency shift, than if it was placed at the crystal edge, Fig. 2.

Mass sensitivity

Figure 2. Illustration of how the frequency shift caused by a localized mass deposited at the sensor surface depends on where the mass is placed. The mass sensitivity varies with the sensor radius according to a Gaussian function (Fig. 1). Therefore, a mass deposited at the rim (A) will generate a smaller frequency shift than if the mass is deposited closer to the middle (B). Mass deposition at the middle (C) will generate the largest response.

Consequences of uneven mass distribution in a measurement situation

The frequency shift that is recorded in a measurement is the sum of all local (force) contributions from the entire sensor surface. We are now at the crux of the problem. Placing 1000 particles at the peripheral could give the same frequency shift as placing 10 of those particles close to the center of the sensor, or vice versa. This means that the same number of particles (i.e. same total mass) can give different frequency shift depending on how they are distributed on the sensor surface. So, if you don’t know the mass distribution of the particles/film you are measuring, it is not possible to reliably convert a frequency shift to a total mass of the particles/film.

Relative changes may be absolutely right

Is all then lost if you have uneven and unknown mass distribution? Not quite: If all particles change their mass by X%, then the sum of forces (and the measured frequency shift) will also change by X% regardless of how the particles are distributed. This means that you can still compare the relative change in one mass distribution with another.

An example could be that you want to determine which of a set of detergents best removes fingerprints. You would likely get different frequency shifts due to the fingerprint depending on where you place it on the sensor. But you can still evaluate the detergents’ efficacy by comparing how quickly they remove say 90% of the fingerprints’ initial frequency shift.

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